Are the vectors 3 2 1 3 4 4 and 4 3 0 linearly independent I
Are the vectors [-3 2 1], [-3 4 -4] and [4 -3 0] linearly independent? If they are linearly dependent, find scalars that are not all zero such that the equation below is true. If they are linearly independent, find the only scalars that will make the equation below true. [-3 2 1]+ [-3 4 -4]+ [4 -3 0] = [0 0 0].
Solution
Your matrix
Find the pivot in the 1st column and swap the 3rd and the 1st rows
Eliminate the 1st column
Make the pivot in the 2nd column by dividing the 2nd row by 12
Eliminate the 2nd column
Make the pivot in the 3rd column by dividing the 3rd row by 1/4
Eliminate the 3rd column
solution
x1 = 0
x2 = 0
x3 = 0
all scalasr are zero linearly independent
| X1 | X2 | X3 | b | |
|---|---|---|---|---|
| 1 | -3 | -3 | 4 | 0 |
| 2 | 2 | 4 | -3 | 0 |
| 3 | 1 | -4 | 0 | 0 |
![Are the vectors [-3 2 1], [-3 4 -4] and [4 -3 0] linearly independent? If they are linearly dependent, find scalars that are not all zero such that the equatio Are the vectors [-3 2 1], [-3 4 -4] and [4 -3 0] linearly independent? If they are linearly dependent, find scalars that are not all zero such that the equatio](/WebImages/42/are-the-vectors-3-2-1-3-4-4-and-4-3-0-linearly-independent-i-1129197-1761602858-0.webp)