The rate constant for the reaction is 0360 M151 at 200 A pro

The rate constant for the reaction is 0.360 M-151 at 200 A products If the initial concentration of A is 0.00240 M, what will be the concentration after 405 s? click to edit Number

Solution

from the units of rateconstant it is clear reaction is second order

for second order

1 / [A] = Kt + 1/[A₀]

[A₀] = 0.00240 M

1/ [A] = 0.360 x 405 + 1/ 0.00240

1/ [A] = 145.8 + 416.7

1/[A] = 562.5

[A] = 0.00178 M