CH2OH B HO HO HO Fehlings reagent HOCH2 Sucrose CH2OH OH C H

CH2OH B. HO HO HO Fehling\'s reagent HOCH2 Sucrose -CH2OH OH C. HO CH2OH CH2OH O Fehling\'s reagent HO OH HO OH -Lactose

Solution

In reaction B. NO PRODUCT will be formed.

In reaction C. reaction would take place and lead to the formation of rust red precipitate hence confirming the presence of reducing sugar.

Reason:

1. Fehling\'s reagent is used for determining the presence of reducing sugars and the test is called Fehling\'s test.

2. The positive result of the test give red rust precipitate confirming the presence of reducing sugars.

3. Fehling\'s test used for reducing sugars like glucose, fructose, glyceraldehyde, lactose, arabinose and maltose.

4. Sucrose is a non-reducimg sugar hence no reaction will take place.