Which IP addressing scheme is correct about the topology dis

Which IP addressing scheme is correct about the topology displayed in the exhibit? host 1 192.168.10.22/24; host 2 192.168.10.23/24; host 3 192.168.11.23/24 host 1 192.168.10.22/24; host 2 192.168.10.23/24; host 3 192.168.10.24/24 host 1 192.168.10.22/24; host 2 192.168.11.23/24; host 3 192.168.10.23/24. host 1 192.168.11.22/24; host 2 192.168.11.23/24; host 3-192.168.10.24/24 26. Which command will create a dynamic pool named Todd that will provide you with 30 global addresses?

Solution

Answer:

Host 1 and Host 3 are in the same network , that means their network id should be same : 192.168.10 is the network ID of both the hosts.

The Host 2 is in different network, so its network ID should be different than Host 1 and Host 2. Therefore the correct answer is

c) host 1 - 192.168.10.22/24;

host 2 - 192.168.11.23/24

host 3 - 192.168.10.23