I need intructions on how to do the problem in EXCEL In dete

I need intructions on how to do the problem in EXCEL.

In determining automobile-mileage ratings, it was found that the mpg (X) for a certain model is normally distributed, with a mean of 33 mpg and a standard deviation of 1.7 mpg. Find the following: p(X less than 30) P(28 less than X less than 32 P(X greater than 35) P(X greater than 31) The mileage rating that the upper 5% of cars achieve.

Solution

a)The z score is:

z=(x-)/=(30-33)/1.7=-1.76

P(x<30)=P(z<-1.76)=0.0392

b)P(28<x<32)=P(x<32)-P(x<28)

z1=(32-33)/1.7=-0.58

z2=(28-33)/1.7=-2.9

P(z1<-0.58)-P(z2<-2.9)=0.2810-0.0183=0.2627

c)P(x>35)=1-P(x<35)=1-(z<1.76)=0.9608

I need intructions on how to do the problem in EXCEL. In determining automobile-mileage ratings, it was found that the mpg (X) for a certain model is normally d

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