Determine the roots and axis of symmetry for the following q

Determine the root(s) and axis of symmetry for the following quadratic functions. Enter your answer as a single number of a string of numbers. Separate multiple answers with commas and if there are no roots write DNE. (For example, if the roots are 3 and 4 enter 3,4) a. f(x)= 6x2+6x-1 1. Root(s) of t: -1.15,0.15 Preview ii. Axis of symmetry of f: x --1/2 Preview b. g(z)- (x- 10)(- 7x - 8) i. Root(s) of g: «Preview 11. Axis of symmetry of g: X Preview i. Root(s) of h: Preview ii. Axis of symmetry of h: x Preview

Solution

6x^2 + 6x - 1 = 0

-b +/- sqrt(b^2 - 4ac) / 2a

-6 +/- sqrt(36 + 24) / 12

-6 +/- sqrt(60) / 12

(-6 +/- 2sqrt(15)) / 12

(-3 + sqrt(15))/6 and (-3 - sqrt(15))/6

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b)
(x - 10)(-7x - 8) = 0

x - 10 = 0 , -7x - 8 = 0

x = 10 and x = -8/7

ii)
The axis of symmetry is just the average of the zeros...
(10 + -8/7) / 2

x = 31/7

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c)
x^2 - 2x - 15 = 0

(x - 5)(x + 3) = 0

x = 5 and x = -3

ii)
AoS = (5 + (-3))/2

AoS : 2/2 = 1

x =1