Analyze the following code public class Test public static
Analyze the following code. public class Test { public static void main(String[] args) { int n = 2; xMethod(n); } public static void xMethod(uit n) { n++, System.out.println(\"n is\" + n); Return n; } } a. The code prints n is 1. b. The code prints n is 2. c. The code prints n is 3. d. The code has a syntax error because xMethod returns a value.
Solution
Ans)d
Reason:
the method xMethod signature we provided as void.But we are writing Return statement inside the method body which results syntax error.
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![Analyze the following code. public class Test { public static void main(String[] args) { int n = 2; xMethod(n); } public static void xMethod(uit n) { n++, Syst Analyze the following code. public class Test { public static void main(String[] args) { int n = 2; xMethod(n); } public static void xMethod(uit n) { n++, Syst](/WebImages/42/analyze-the-following-code-public-class-test-public-static-1129805-1761603312-0.webp)