Analyze the following code public class Test public static
     Analyze the following code.  public class Test  {  public static void main(String[] args)  { int n = 2;  xMethod(n);  }  public static void xMethod(uit n)  {  n++,  System.out.println(\"n is\" + n);  Return n;  }  }  a. The code prints n is 1.  b. The code prints n is 2.  c. The code prints n is 3.  d. The code has a syntax error because xMethod returns a value.![Analyze the following code. public class Test { public static void main(String[] args) { int n = 2; xMethod(n); } public static void xMethod(uit n) { n++, Syst  Analyze the following code. public class Test { public static void main(String[] args) { int n = 2; xMethod(n); } public static void xMethod(uit n) { n++, Syst](/WebImages/42/analyze-the-following-code-public-class-test-public-static-1129805-1761603312-0.webp) 
  
  Solution
Ans)d
Reason:
the method xMethod signature we provided as void.But we are writing Return statement inside the method body which results syntax error.
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![Analyze the following code. public class Test { public static void main(String[] args) { int n = 2; xMethod(n); } public static void xMethod(uit n) { n++, Syst  Analyze the following code. public class Test { public static void main(String[] args) { int n = 2; xMethod(n); } public static void xMethod(uit n) { n++, Syst](/WebImages/42/analyze-the-following-code-public-class-test-public-static-1129805-1761603312-0.webp)
