In the laboratory a student finds that it takes 158 Joules t

In the laboratory a student finds that it takes 158 Joules to increase the temperature of 13.1 grams of solid aluminum from 25.0 to 39.3degrees Celsius.

The specific heat of aluminum calculated from her data is ? J/g°C

Solution

We have q = 158 J mass of aluminium = 13.1 gm & T₁ =25°C , T₂ =39.3°C

q = (mass) (change in temp) (specific heat)

158 J = 13.1 gm (39.3°C – 25°C) (X)

X =158J /(13.1gm x 14.3°C) = 0.8434 J /g°C

X = 0.8434 J /g°C

so for Aluminum metal specific heat = 0.8434 J /g°C