The average value of a certain type of automobile was 15 300

The average value of a certain type of automobile was $15, 300 in 1993 and depreciated to $6840 in 1996. Let y be the average value of the automobile in the year x, where x = 0 represents 1993. Write a linear equation that models the value of the automobile in terms of the year x. y = - 2820x + 6840 y = - 2820x 1620 y = 1/2820 x - 6840 A vendor has learned that, by pricing, caramel apples at $1.50, sales will reach 82 Carmel apples per day. Raising the price to $2.50 will cause the sales to fall to 34 caramel apples per day. Let y be the number of caramel apples the vendor sells at x dollars each. Write a linear equation that models the number of caramel apples sold per day when the price is x dollars each. y = - 48x - 154 y = 1/48 x + 2623/32 y = - 48 x + 154

Solution

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As per data given in the question it is clear that we have to deduce a linear relation such that the line passes thorugh the points (0,15,300) & (3,6840)

Now using equation of a line passing through two given points e have

(y - y1) = [ (y2-y1) / (x2-x1)]* (x-x1)

=> (y - 15300) = [(6840 -15300)/3]*(x - 0)

y = -2820x + 15300

Solution (D)

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