Homework SourseThe Class C subnets are A network administrator says the add
The Class C subnets are:
A network administrator says the address to manually assign to a new printer is: 192.168.1.133 /27
1. Is this a valid IP address and CIDR?
2. If yes, which IP Subnetwork is this device in?
3. What is the subnet mask in decimal form?
4. What is the value in Binary of the subnet mask’s 4th octet?
5. With only this address used so far in this subnet, how many remain for assignment to other devices?
6. Can 192.168.1.128 be used for a device? If no, why?
7. Can 192.168.1.191 be used for a device? If no, why?
| IP Subnetwork | Host IP Range | Broadcast Address |
| 192.168.1.32 | .33 -- .62 | 192.168.1.63 |
| 192.168.1.64 | .65 -- .94 | 192.168.1.95 |
| 192.168.1.96 | .97 -- .126 | 192.168.1.127 |
| 192.168.1.128 | .129 -- .158 | 192.168.1.159 |
| 192.168.1.160 | .161 -- .190 | 192.168.1.191 |
| 192.168.1.192 | .193 -- .222 | 192.168.1.223 |
Solution
Answer:
1) Yes it is a valid IP address and CIDR
2) Its IP subnetwork is : 192.168.1.128
3) Since the IP is divided into 5 subnets , that means 5 bits are choosen from the network part , therefore subnet mask = 255.255.255.248
4) The binary value of subnet mask\'s 4th octet = 248 and it is 11111000
6) 192.168.1.128 cannot be assigned to any device because in a subnetwork , the first and the second IP address are reserved.
7) Same reason for this too.
