Solve the following logarithmic equation algebraically log3

Solve the following logarithmic equation algebraically. log_3 (x) + log_3(x - 1) = log_3 6 Select the correct choice below and, if necessary, fill in A. The solution is x = (Simplify your answer. Type an integer or a fraction B. The solution is not a real number.

Solution

log₃x + log₃(x-1)=log₃6

log₃(x(x-1)) = log₃6

x²-x-6=0

(x-3)(x+2)=0

x=3,-2

log cant take negative numbers

therefore x=3