Consider the triangle shown below not drawn to scale Let c

Consider the triangle shown below (not drawn to scale). Let c = 4, angle C = 110 degree and angle B = 40 degree. Find the measure of angle A (in degrees) and the lengths of sides a and b. Give your answer to at least 3 decimal places. Angle A = a = b =

Solution

c=4 , <C=110 degree, <B=40

<A=180-C-B=30 degree

using sine law

sin C/c=sinB/b

sin110/4=sin40/b

b= 4 sin 40/sin 110=2.736

sinC/c=sinA/a

sin 110/4=sin 30/a

a= 4 sin 30/sin 110=2.128