Use part I of the Fundamental Theorem of Calculus to find th
Use part I of the Fundamental Theorem of Calculus to find the derivative of
h\'=???
h(x) = (cos(t3) + t) dtSolution
[cos(sin^3 (x)) + sinx ] * cosx this is derivative rule for any integrated thing here put the upper limit in place of variable t and in place of dt put derivative of upper limit that is sinx which is equal to cosx then put minus sign and do the same thing with lower limit here derivative of lower limit is 0 thats why i have written 0![Use part I of the Fundamental Theorem of Calculus to find the derivative of h\'=??? h(x) = (cos(t3) + t) dtSolution [cos(sin^3 (x)) + sinx ] * cosx this is deri Use part I of the Fundamental Theorem of Calculus to find the derivative of h\'=??? h(x) = (cos(t3) + t) dtSolution [cos(sin^3 (x)) + sinx ] * cosx this is deri](/WebImages/42/use-part-i-of-the-fundamental-theorem-of-calculus-to-find-th-1130511-1761603833-0.webp)