Write a program that will calculate the log base 2 of an int

Write a program that will calculate the log base 2 of an integer. The log base 2 can be easily calculated by counting the number of times you have to shift a number to the right before it is one. #include using namespace std; int main(int argn, char *argv[]) {int number, log; cout > number; _asm {//Calculate the logz of number and store the result in log} cout

Solution

#include<iostream>
#include<cmath>
using namespace std;

int main(int argc, char const *argv[])
{
   int number,log;
   cout<<\"Enter a number\ \";
   cin>>number;
   _asm
   {
       log=log(number)/log(2);
   }

   cout<<\"Logarithm is \"<<log<<endl;
   return 0;
}

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Output:

Enter a number

3

Logarithm is 1.584962501