Sapling Learning Enough of a monoprotic acid is dissolved in

Sapling Learning Enough of a monoprotic acid is dissolved in water te sroduce a 0.0167 M solution. The pH of the resulting solution is 2.37. Calculate the Ka for the acid Hint

Solution

PH   = 2.37

-log[H^+]   = 2.37

[H^+]   = 10^-2.37   = 0.004265M

     HA is weak mono protic acid

          HA -------------> H^+ (aq) + A^-

I         0.0167                0            0

C       -0.004265        0.004265   0.004265

E       0.012435         0.004265    0.004265

      Ka   = [H^+][A]/[HA]

    Ka   = 0.004265*0.004265/0.012435

           = 0.00146   = 1.46*10^-3 >>>>>answer