Hello I have a couple questions I need some help with dealin

Hello, I have a couple questions I need some help with dealing with assembly language and MASM. Walking through one of them is good enough.

The four-byte sequence 0x92 0x8A 0x8A 0x57 stored in consecutive memory cells in a little-endian architecture represents ___________ (decimal) when interpreted as a 32-bit signed integer.

The four-byte sequence 0xF6 0x45 0x71 0x85 stored in consecutive memory cells in a little-endian architecture represents ___________ (decimal) when interpreted as a 32-bit signed integer.   

The four-byte sequence 0xD6 0x85 0x41 0xA0 stored in consecutive memory cells in a little-endian architecture represents ___________ (decimal) when interpreted as a 32-bit signed integer.   

The four-byte sequence 0x87 0x8B 0xDD 0x6A stored in consecutive memory cells in a little-endian architecture represents ___________ (decimal) when interpreted as a 32-bit signed integer.   

The four-byte sequence 0x8D 0x0C 0x52 0xDB stored in consecutive memory cells in a little-endian architecture represents ___________ (decimal) when interpreted as a 32-bit unsigned integer.   

The four-byte sequence 0x22 0x86 0x82 0x56 stored in consecutive memory cells in a little-endian architecture represents ___________ (decimal) when interpreted as a 32-bit unsigned integer.   

Solution

Mark the questions from 1 to 6 one by one.

1.

The correct answer to fill the blank is 1468697234.0

Explanation:

As per the architecture of little-endian, the least significant byte has been stored first. Therefore, the significant bytes are stored as given below:

Therefore, signed integer would be (578A8A92)₁₆.

So, the computation for computing the decimal value would be as follows:

= 2 * 16⁰ + 9 * 16¹ + A * 16² + 8 * 16³ + A * 16⁴ + 8 * 16⁵ + 7 * 16⁶ + 5 * 16⁷

= 2 + 144 + 10 * 16² + 32768 + 10 * 16⁴ + 8388608 + 117440512 + 1342177280

= 1468039314 + 2560 + 655360

= 1468697234

Thus, the correct answer is 1468697234.0 (with the margin as 0).

2.

The correct answer to fill the blank is 2238793206.0

Explanation:

As per the architecture of little-endian, the least significant byte has been stored first. Therefore, the significant bytes are stored as given below:

Therefore, signed integer would be (857145F6)₁₆.

So, the computation for computing the decimal value would be as follows:

= 6 * 16⁰ + F * 16¹ + 5 * 16² + 4 * 16³ + 1 * 16⁴ + 7 * 16⁵ + 5 * 16⁶ + 8 * 16⁷

= 6 + 15 * 16¹ + 1280 + 16384 + 65536 + 7340032 + 83886080 + 2147483648

= 1468039314 + 2560 + 655360

= 2238793206

Thus, the correct answer is 2238793206.0 (with the margin as 0).

3.

The correct answer to fill the blank is 2688648662.0

Explanation:

As per the architecture of little-endian, the least significant byte has been stored first. Therefore, the significant bytes are stored as given below:

Therefore, signed integer would be (A04185D6)₁₆.

So, the computation for computing the decimal value would be as follows:

= 6 * 16⁰ + D * 16¹ + 5 * 16² + 8 * 16³ + 1 * 16⁴ + 4 * 16⁵ + 0 * 16⁶ + A * 16⁷

= 6 + 13 * 16¹ + 1280 + 32768 + 65536 + 4194304 + 0 + 10 * 16⁷

= 2688648662

Thus, the correct answer is 2688648662.0 (with the margin as 0).

4.

The correct answer to fill the blank is 1792904071.0 (with the margin as 0)

Explanation:

As per the architecture of little-endian, the least significant byte has been stored first. Therefore, the significant bytes are stored as given below:

Therefore, signed integer would be (6ADD8B87)₁₆.

So, the computation for computing the decimal value would be as follows:

= 7 * 16⁰ + 8 * 16¹ + B * 16² + 8 * 16³ + D * 16⁴ + D * 16⁵ + A * 16⁶ + 6 * 16⁷

= 7 + 128 + 11 * 16² + 32768 + 13 * 16⁴ + 13 * 16⁵ + 10 * 16⁶ + 1610612736

= 1792904071

Thus, the correct answer is 1792904071.0 (with the margin as 0).

5.

The correct answer to fill the blank is 3679587469.0 (with the margin as 0)

Explanation:

As per the architecture of little-endian, the least significant byte has been stored first. Therefore, the significant bytes are stored as given below:

Therefore, signed integer would be (DB520C8D)₁₆.

So, the computation for computing the decimal value would be as follows:

= D * 16⁰ + 8 * 16¹ + C * 16² + 0 * 16³ + 2 * 16⁴ + 5 * 16⁵ + B * 16⁶ + D * 16⁷

= 13 + 128 + 3072 + 0 + 131072 + 5242880 + 184549376 + 3489660928

= 3679587469

Thus, the correct answer is 3679587469.0 (with the margin as 0).

6.

The correct answer to fill the blank is 1451394594.0 (with the margin as 0)

Explanation:

As per the architecture of little-endian, the least significant byte has been stored first. Therefore, the significant bytes are stored as given below:

Therefore, signed integer would be (56828622)₁₆.

So, the computation for computing the decimal value would be as follows:

= 2 * 16⁰ + 2 * 16¹ + 6 * 16² + 8 * 16³ + 2 * 16⁴ + 8 * 16⁵ + 6 * 16⁶ + 5 * 16⁷

= 2 + 32 + 1536 + 32768 + 131072 + 8388608 + 100663296 + 1342177280

= 1451394594

Thus, the correct answer is 1451394594.0 (with the margin as 0).