A triangular parking lot is bounded by three streets as show
A triangular parking lot is bounded by three streets as shown. The distance between each intersection is shown on the picture and is given in feet.
Solution
dropping a perpendicular from the intersection of schleter st and bennett blvd to McCord Maze
let it be d
let the triangle formed by three sides be ABC
finding the angles of the triangle
by law of cosines
angle A = cos^-1 [ 218^2 + 334^2 - 252^2 ] / ( 2*218*334)
A = 48.98 degrees
similarly finding B
B = 40.74 degrees
C = 90.27 degrees
now applying sine rule
sin A = d / 218
d = sin A * 218
d = 164.47
therefore, shortest distance is 164.47 feet
