Help due soon 4 299 2710 PM s rationalreasoningneta Q 13 lli
Help!! due soon!.
4 299, 27:10 PM s rationalreasoning.net/a Q 13 llill Q 11 11/11 C 015 (0.311) Q 16 [111] c Q 17 (0.911) Gradc: 15.6117 Print Version Tim is on a Fcrris whccl with a 26 foot radius. JL Lakes him 262 seconds Lu compl ctc onc rcwolution on thc Fcrris wheel a. Determine the constant spcod (in radians per second) Lhat Jim ravels whilc riding the Ferris whccl. radians C2398 16 per secund Preview b. Define a function m that determines Tim\'s vertical distance above the horizontal diameter of the Ferris wheel (in radii) in terms of the number of seconds elapsed, L, since Tim started to rotate from the 3 o\'clock position mit frsin(07398 PreviewSolution
Angle covered in one second= 360/262=1.3846 degree.
1.3846o= 0.02461 radian
Distance function m(t)= 26sin (0.02461 t)
![Help!! due soon!. 4 299, 27:10 PM s rationalreasoning.net/a Q 13 llill Q 11 11/11 C 015 (0.311) Q 16 [111] c Q 17 (0.911) Gradc: 15.6117 Print Version Tim is o Help!! due soon!. 4 299, 27:10 PM s rationalreasoning.net/a Q 13 llill Q 11 11/11 C 015 (0.311) Q 16 [111] c Q 17 (0.911) Gradc: 15.6117 Print Version Tim is o](/WebImages/42/help-due-soon-4-299-2710-pm-s-rationalreasoningneta-q-13-lli-1131152-1761604310-0.webp)