Part B If you take a 135mL portion of the stock solution a M

Part B If you take a 13.5-mL portion of the stock solution a M. Incorrect, Try Again; 5 attempts remaining Provide Feedback 26 8

Let the concentration of stock solution be, \'a\' M

Now, the new concentration = (no. Of moles )/volume of solution (in litre)

no. Of moles = molarity x volume (in L)= aX (13.5/1000)

Since , the new total volume is 0.7 M

Hence , the new concentration =[( a X (13.5/1000))/0.7] M

Just place the value of \'a\' i.e molarity (concentration) of stock solution, you\'ll get the answer.