Homework SourseWhat is the equilibrium constant expression for the followin
What is the equilibrium constant expression for the following reaction:
PtCl42(aq)Pt2+(aq) + 4Cl(aq)
Choose from the list below and enter the letters alphabetical order. (e.g. For an equilibrium constant of [Cl-]4eq[Pt2+]eq enter AH.)
L) [PtCl42-]-4eq
It says the answer is not AHF and i don\'t know what else to try
| A) [Pt2+]eq | E) [Cl-]-1eq | I) [PtCl42-]4eq |
| B) [Cl-]eq | F) [PtCl42-]-1eq | J) [Pt2+]-4eq |
| C) [PtCl42-]eq | G) [Pt2+]4eq | K) [Cl-]-4eq |
| D) [Pt2+]-1eq | H) [Cl-]4eq | L) [PtCl42-]-4eq |
Solution
Equilibrium constant
K = [Pt^2+]eq[Cl^-]^4 eq / [PtCl4^2-]eq
K = AH / C = AH*F = AHF
