fx 5x 3 gx 6x 5 Find fg fx 5x 3 gx 6x5 Find fg 6x5 5x

f(x) = 5x + 3; g(x) = 6x - 5

Find f/g.

f(x) = 5x + 3; g(x) = 6x-5 Find f/g. 6x-5 5x 3 5 6 (fg)(x) = 5x +3 6x-5 3 (f/g)(x) = domain {xlx 5x +3 6x-5 5 6 (fg)(x) = domain {x 6x-5 5x 3 3 5 (f/g)(x) =

Solution

Divide them, we get :
(5x + 3) / (6x - 5)

Now, denominator cant be ZERO
6x - 5 = 0
6x = 5
x = 5/6

So, x cannot be 5/6

And thus, we have :
Option C