KINETICS AND EQUILIBRIUM Expressing the concentration of an

KINETICS AND EQUILIBRIUM -Expressing the concentration of an intermediate in terms Consider the following elementary reaction: NO 2(9) +03(9) NO3(9) +02(9) e let k stand for the rate constant of this reaction, and k stand for the rate constant of the reverse reaction. Write an expression that gives the equilibrium concentration of NO2 in terms of k,kI, and the equilibrium concentrations of Oy, NO, and O2 [No,]-D

Solution

NO2(g) + O3(g) <------> NO3(g) + O2(g)

rate law for forward reaction is

rate = k₁[NO2][O3]

rate law for reverse reaction is

rate = k_-1[NO3][O2]

at equillibrium

rate of forward reaction = rate of reverse reaction

k₁[NO2][O3]= k_-1[NO3][O2]

[NO2] =( k_-1/k₁) ([NO3] [O2] /[O3])