I have seen many contradictory answers to this question and

I have seen many contradictory answers to this question, and I would like to be a little more confident that I have the correct answer. Can you please do all of the work from scratch and explain what you\'re doing for EACH part? Thank you :)

GEBam 8 EBRA 2 Exam 8 continued Student\'s Name The shape of the Gateway Arch in St. Louis. Missouri, can be approximately modeledhe Student Number 16. the equations of two pa rabolas: one parabola for the outer/upper surface, and one approximately modeled with ienerilower surface. The height of the arch is 630 feet, and at ground of the bases are 630 feet apart. The arch narrows as it bases are only 540 feet apart at ground level, but the inside of the arch has a height f feet. Suppose you are standing at the origin which is at ground level directly underneath the center of the arch. as: one parabola for the outer/upper surface, and one for the level the outsides rises. Therefore, the insides of the inner of 615 a. Find the vertex and x-intercepts for both the outer and inner parabolas. Outer parabola: vertex: Inner parabola: vertex: b. Find the height above the ground of the focus and directrix for each parabola. Round x-intercepts: x-intercepts: your answers to the nearest tenth of a foot. Outer parabola: focus height:- directrix height: Inner parabola: focus height: c. Find the equation for both the outer and inner parabolas in standard form. directrix height Inner parabola: Outer parabola: (over) 1083 61

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