Let v and a denote the velocity and acceleration vectors of
Let v and a denote the velocity and acceleration vectors of a particle moving on a path c. Suppose the initial position of the particle is c(0) = (3,4,0), the initial velocity is v(0) = (1,1,-2), and the acceleration function is a(t) = (0,0,6). Find v(t) and c(t).
Solution
a = 6k so only z component of v is affected v = u+at v = 1i + 1j -2(6)k = (1,1,-12t) \\(s = ut + \\frac{1}{2}at^2\\) c = (3+ 1t)i + (4+1t)j + (-2t + \\frac{1}{2}6t^2)\\)