The solubility of AgCl s in water at 25C is 133 105 molL and

The solubility of AgCl (s) in water at 25C is 1.33 *10^-5 mol/L and its Delta H of solution is 65.7 kJ/mol.

What is its solubility at 41.8C?

dG = -RT ln K sp , at 25C =298 K

Ksp =[Ag+][Cl-] =s^2= (1.33x10^ -5)^2 = 1.77 x10^ -10 ,

dG = -8.314x298 x2.3 log(1.77 x10^ -10)

= 55571 Joules,

dG = dH-TdS ,

55571= 65700-298 xdS , dS = 33.99,

at 41.8C = 314.8 K

dG = 65700-(314.8x33.99) = 55000 ,

now 55000 = -8.314x314.8 lnKsp

Ksp = 7.47 x10^ -10 =s^2,

s=solubility = 2.73 x10^ -5 mol/L