Find the vertex axis of symmetry xintercepts and yintercept

Find the vertex, axis of symmetry, x-intercepts, and y-intercept of the parabola that has the given focus (-3/2,0) and the directrix

y=1/2. Sketch the graph.

focus(-3/2,0)=(h,k+1/4a)

h=-3/2

k+1/4a=0

directix,y=1/2

k-1/4a=1/2

k=1/4

1/4+1/4a=0

a=-1

y=-(x+3/2)^2 +(1/4)

vertex=(-3/2,1/4)

y intercept

y=(3/2)^2+1/45/2

axis of symmetry

x+3/2=0

x=-3/2