A shaper machines a 2 mm layer of material from the surface

A shaper machines a 2 mm layer of material from the surface of a low carbon steel work piece. The work piece is 150 mm wide and 200 mm long. The shaper operates at 50 strokes per minute, with a stroke of 250 mm. The angle of the tool cutting edge is 30 degree and the fee is 0.25 mm per stroke. Calculate the metal removal rate, power required and estimate the time to remove the 2 mm layer.

Solution

Time=L*W*(1+m)/(1000*f*V)

L= Length of the cutting stroke=250mm

W=width of the workpiece=150mm

m= ratio of return time to cutting time=1 (As it is not given)

V= Cutting speed=N*L*(1+m)/1000 m/min

f=feed in mm/cutting stroke

N = no. of stroke per min

MRR= 1000*V*d*f

d= Depth of cut=2 mm

For power K should be given which is constant for calculating the power

Put the value you will get the answer.

If you have any problem then let me know

Thanks