Note It is recommended that you save your response as you co

Note: It is recommended that you save your response as you complete each question. Question 1 (10 points) A 0.4765 g sample of CaCO3 is dissolved in 12 M HCI and diluted to 400.0 mt in a volumetric flask. How many motes of CaCO3 (Mw = 100.1 g/mol) are present in the sample? Express answers as decimals, not exponents Your Answer Answer units Save Question 2 (10 points) SUS

Solution

Number of moles of CaCO3 = mass of CaCO3 / molar mass of CaCO3

number of moles of CaCO3 = 0.4765 g / 100.1 g/mol = 0.004760 mol

Therefore, the number of moles of CaCO3 = 0.004760