Solve the triangle a10 b6 C 70 C Round to two decimal place

Solve the triangle. a=10, b-6, C = 70 C (Round to two decimal places as needed.) (Type your answer in degrees. Round to one decimal place as needed.) (Type your answer in degrees. Round to one decimal place as needed.)

Solution

a = 10 , b = 6 , C = 70

applying law of cosines to find c

c^2 = a^2 + b^2 - 2ab cos C

c^2 = 10^2 + 6^2 - 2(10)(6) cos 70

c = 9.74

applying law of sines

a / sin A = c / sin C

10 / sin A = 9.74 / sin 70

A = 74.7 degrees

B = 180 - ( 74.7 + 70 )

B = 35.3 degrees