Please solve using code not on paper doesnt matter which pro
Solution
#include <iostream>
#include <cmath>
using namespace std;
main(){
int a,b,n;
cout << \"Enter upper limit, b:\"; cin >> b;
cout << \"Enter lower limit, a:\"; cin >> a;
cout << \"\ Enter number of Simpson\'s interval, n (even number only):\"; cin >> n;
long double dx, t=0;
dx = (long double)(b-a)/n;
long double fx[n+1];
for(int i=0;i<=n;i++){
if (i == 0){
t = a;
}
else if (i == n){
t = b;
}
else{
t = a+(i*dx);
}
//cout << \"t = \" << t << endl; // im just curious to know
fx[i] = (1.36*pow(10,-10))*t*t*t*t - (1.23*pow(10,-7))*t*t*t + (4.12*pow(10,-6))*t*t + (3.95*pow(10,-4))*t - (8.58*pow(10,-2));
//fx[i] = (double)1 / (t + 1 );
//cout << \"fx[\" << i << \"] = \" << fx[i] << endl; // im just curious to know
}
long double sum = 0, area = 0;
for (int i=0;i<=n;i++){
if (i == 0 || i == n){
sum = sum + fx[i];
}
else if( i%2 == 0){
sum = sum + 2*fx[i];
}
else {
sum = sum + 4*fx[i];
}
}
area = (dx/3)*sum;
cout << \"sum = \" << sum << endl;
cout << \"dx = \" << dx << endl;
cout << \"\ The Area is = \" << area << endl;
return 0;
}

