Calculate the net work output of a heat engine following pat

Calculate the net work output of a heat engine following path ABCDA in the figure below, where

V₁ = 5.6 10³ m³

and

V₂ = 22.4 10³ m³.

How is the work done measured for an enclosed loop in the case of a heat engine? J

Solution

the work done measured for an enclosed loop in the case of a heat engine = Area of ABCDA

Area of ABCDA = Area of dashed rectangle +Area of the upper triangle -Area of lower triangle

                       = [(2-0.6)x10 ⁶ x (V2-V1)] +[(1/2)(V2-V1)(2.6-2)x10 ⁶ ]- [(1/2)(V2-V1)(1-0.6)x10 ⁶ ]

                      =(V2-V1) [ (1.4 x10 ⁶ )+(0.3x10 ⁶) -(0.2 x10 ⁶) ]

                      =[(22.4 -5.6)x10 ^-3 ] [1.5 x10 ⁶]

                      = 25200 J