How many amps are required to produce 287 g of lithium metal

How many amps are required to produce 28.7 g of lithium metal from a sample of molten lithium chloride in 6.83 hours?

Solution

moles of Lithium = 28.7 / 6.941 = 4.135 moles

Moles of e- = 4.135

=> Charge = 4.135 x 1.602 x 10^-19 x 6.022 x 10^23 = 398899.154 C

charge = 398899.154 = 6.83 x 3600 x Current

=> Current = 16.223 Ampere

 How many amps are required to produce 28.7 g of lithium metal from a sample of molten lithium chloride in 6.83 hours?Solutionmoles of Lithium = 28.7 / 6.941 =

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