How many amps are required to produce 287 g of lithium metal
How many amps are required to produce 28.7 g of lithium metal from a sample of molten lithium chloride in 6.83 hours?
Solution
moles of Lithium = 28.7 / 6.941 = 4.135 moles
Moles of e- = 4.135
=> Charge = 4.135 x 1.602 x 10^-19 x 6.022 x 10^23 = 398899.154 C
charge = 398899.154 = 6.83 x 3600 x Current
=> Current = 16.223 Ampere
