May I please have assistance with writing a JAVA program tha

May I please have assistance with writing a JAVA program that generates 10 random doubles, all between 1 and 11, and writes them to a text file, one number per line. Then I need to write another JAVA program that reads the text file and displays all the doubles and their sum accurate to two decimal places.

SAMPLE OUTPUT:

10.6269119604172

2.737790338909455

5.427925738865128

1.3742058065472509

1.1858700262498836

4.180391276485228

4.910969998930675

5.710858234343958

7.790857007373052

3.1806714736219543

The total is 47.13

Solution

package chegg;

import java.io.FileWriter;
import java.io.IOException;
import java.io.PrintWriter;
import java.util.Random;

public class WriteIntoFile {
  
   public static void main(String args[])
   {
       String path = \"/Users/swapnil/Documents/input.txt\";
       double r;
       PrintWriter print_line;
       FileWriter write;
      
       try {
           write = new FileWriter(path, false);
           print_line = new PrintWriter(write);
      
           Random randomGenerator = new Random();
           for (int idx = 1; idx <= 10; ++idx){
               r = 1 + randomGenerator.nextDouble()*10;
               System.out.println(r);
               print_line.printf(\"%f\" + \"%n\", r);
           }
           print_line.close();
       } catch (IOException e) {
           e.printStackTrace();
   }
      
      
   }
}

/************** Read **********/

package chegg;

import java.io.BufferedReader;

import java.io.FileReader;

import java.io.IOException;

public class ReadFromFile {

   public static void main(String[] args) {

       String path = \"/Users/swapnil/Documents/input.txt\";

      String line;

       double sum = 0;

       try (BufferedReader br = new BufferedReader(new FileReader(path))) {

          while ((line = br.readLine()) != null) {

             System.out.println(line);

               sum += Double.parseDouble(line.toString());

          }

          System.out.println(sum);

       } catch (IOException e) {

           e.printStackTrace();

       }

   }

}