iven the following reaction at equilibrium at 3000 K NH 4HS

iven the following reaction at equilibrium at 300.0 K: NH 4HS (s) NH 3 (g) + H 2S (g) If pNH 3 = pH 2S = 0.109 atm, K p = __________. .0119 4.99 x 10 -4 .109 5.66 x 10 -3 .0821

Solution

In a given reaction, Kp= [NH3][H2S]. Since the reactant is a solid, it\'s pressure is not considered. Therefore, Kp=0.109×0.109= 0.011881 = 118.81× 10^-4.