Do not use Matlab please show me the steps how to solve it b

Do not use Matlab, please show me the steps how to solve it by hand

Find the indices of the elements in the vector x=cos(0.5).^0.5*n) over 0 lessthanorequalto n lessthanorequalto 100 that lie between 0.45 and 0.65. y=[]; for k=1:length(x) if(x(k)>0.45 &&x;(k)

Solution

first calculate the values for x

from n=0 to n=100

and store it in vector x

FOR EXAMPLE your vector x contains following values

x=[0 0.5 0.2 0.6 ]

as you can see 0.5 and 0.6 lies in range given. Their indexes are 2 and 4.This should be our output.

In order to simullate matlab code above and solving it using hand you will have to do following

declare a vector y[]

check every element of vector x[] and see if it lies in range given.

does 0 lies in range no

does 0.5 lies in range yes

does 0.2 lies in range no

does 0.6 lies in range yes

if yes

store that element in y[]

y[0.5 0.6]

now declare a vector n[]

for every element in y[] find the index of that element from vector x and store in n[]

find index of 0.5 in vector x[] i.e 2 and store it in n[]

find index of 0.6 in vector x[] i.e 4 and store it in n[]

dispalay the contents of n[]

i.e [2 4]

of course if you want to do by hand you can just look into vector x and figure out the index of elemnets in given range