Convert the equation to standard form by completing the squa

Convert the equation to standard form by completing the square on x and y Then graph the elipse and give the location of its foci. 294x 128y-2631 0 The standard form of the equation is Choose the correct graph below. OC. O B. O A. The foci are located at Type ordered pairs. Use a comma to separate answers as needed. Simplify your answers. Type an exact answer, using radicals as needed.)

Solution

49x^2 +64y^2-294x+128y-2631=0

49(x^2 -6x+9-9) +64(y^2 +2y+1-1)=2631

49(x-3)^2 +64(y+1)^2=2631+441+64

(x-3)^2/64 +(y+1)^2/49=1

center(3,-1)

a=8 ,b=7

option c

 Convert the equation to standard form by completing the square on x and y Then graph the elipse and give the location of its foci. 294x 128y-2631 0 The standar

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