Let n N and let PnK be the vector space of all polynomials o
Solution
Solution :- (2) Let V be a vector space over K. V is infinite dimensional.
Suppose V that is infinte dimensional and let (v1, . . . , vn) be a list of linearly independent vectors.
Such a list exits for some n (at least for n = 1 ,since V {0}).
This list cannot span V .
Therefore there exists a vector vn+1 span(v1, v2, . . . , vn) in V .
But now the expanded list (v1, v2, . . . , vn, vn+1) is a list of linearly independent vectors in V .
Since any finite list will not span V , it can be expanded further.
Thus we created a sequence of vectors v1, v2, . . . such that (v1, v2, . . . , vn)
is linearly independent for every positive integer n.
Conversely,
suppose such a sequence exists. Since any spanning list of vectors is
longer thatn any linearly independent list, it follows that any spanning list has
length greater than n for any positive integer n.
Hence, no finite list of vectors will span V and V is infinite dimensional.
