A man rode a bicycle for 12 miles and then hiked an addition

A man rode a bicycle for 12 miles and then hiked an additional 8 miles. The total time for the trip was 5 hours his rate when he was riding a bicycle was 10 miles per h faster than his rate hiking, what was each rate?

Solution

Dear Student Thank you for using Chegg !! Distance when the man rode the bicycle = 12 Miles Distance when the man hiked = 8 miles Total time of trip = 5 hours speed during riding = s+5 miles/hour speed during hiking = s miles/hour Total time of journey is given by = [(12/(s+5)] + 8 / s [(12/(s+5)] + 8 / s = 5 12s + 8(s+5) = 5(s)(s+5) 12s + 8s + 40 = 5s^2 +25s 5s^2 +5s - 40 = 0 s^2 + s - 8 = 0 s=[-1+ sqrt(33)]/2 s = 2.37 miles / hour Hiking rate = 2.37 miles / hour Bikingrate = 7.37 miles / hour Solution