250 points 2 attempts left Check my work How many rings are

2.50 points 2 attempts left Check my work How many rings are present in CisH23103? This compound consumes 2 mol of H2 on catalytic n. Enter your answer in the provided box ring(s)

Solution

degree of unsaturation is given by formula

dn = ( nC x 2+ 2 - nH) / 2 , where nC = 15 , nH = 24 ( we consider Iodine as 1H , Oxygen as 0 H)

dn = ( 15 x 2 + 2 - 24) / 2 = 4

dn = 4 =number of double bonds + number fo rings

dn = 1 corresponds to 1 double bond or 1 ring

now since compound consumes 2 mol of H2 , we had 2 double bonds

hence 4 = 2 + number fo rings

number of rings = 2