1 Body temperatures of healthy adults are normally distribut

1. Body temperatures of healthy adults are normally distributed with a mean of 98.6 oF and a standard deviation of 0.73 oF. What is the probability of a healthy adult having a body temperature less than 99.6 oF or greater than 100.6 oF?

Solution

P ( X < 99.6 or X > 100.6)

= 1 - P( 99.6 < X < 100.6)

= 1 - [ P ( X < 100.6) - P ( X < 99.6) ]

= 1 - [ 0.99692 - 0.91463 ]

= 1 - 0.08229

= 0.91771

Hope this helps.