bAnd what is the magnitude of the forces on the spheres from

b.)And what is the magnitude of the forces on the spheres from the right side of the container?

c.)And what is the magnitude of the forces on the spheres from the bottom of the container?

d.) And what is the magnitude of the forces on the spheres from each other?

e.)If the angle is increased to 90.° think about what happens to the forces. Now consider another angle, 34°. What is now the magnitude of the forces on the spheres from the left side of the container?

f.)And what is now the magnitude of the forces on the spheres from the right side of the container?

g.) And what is now the magnitude of the forces on the spheres from the bottom of the container?

h.) And what is now the magnitude of the forces on the spheres from each other?

Please explain in detail! Thank you!

Solution

part E to H

Since all the surface are frictionless.

The contact force F exerted by lower sphere on the upper sphere is in 34 deg of horizontal.

Forces exerted by walls and floors are in the normal direction of them.

Equilibrium on the top force gives two equations

Fwr = F*cos 34 deg

F*sin 34 deg = m*g

equilibrium of forces on bottom sphere

Fwl = F*cos 34 deg

Ff = F*sin 34 deg + mg

Solving the above four equation gives

force by the bottom of the container

Ff = 2*m*g

force by the contact of esch other

F = mg/sin 34 deg

F = 1.788*m*g

force by left side of container

Fwl = F*cos 34 deg = 1.788*m*g*cos 34 deg

Fwl = 1.482*m*g

force by right side of container

Fwr = F*cos 34 deg = 1.482*m*g