Find all real zeros and state their multiplicities of each p
Find all real zeros (and state their multiplicities) of each polynomial function.
f(x) = 8x3 + 6x2 - 27x
Solution
f(x) = 8x3 + 6x2 - 27x
for zeroes
8x3 + 6x2 - 27x=0
=>x( 8x2 + 6x - 27)=0
=> x =0 , 8x2 + 6x - 27=0
=> x =0 , 8x2 + 6x = 27
=> x =0 , x2 + (3/4)x = (27/8)
=> x =0 , x2 + (3/4)x + (3/8)2= (27/8)+ (3/8)2
=> x =0 , (x + (3/8))2= (27/8)+ (9/64)
=> x =0 , (x + (3/8))2= (225/64)
=> x =0 , (x + (3/8))= (-15/8) , (x + (3/8))= (15/8)
=> x =0 , x = (-18/8) , x = (12/8)
=> x =0 , x = (-9/4) , x = (3/2)
zeroes are x= (-9/4) ,0 , (3/2) with each having multiplicity 1
