A cross is made between double heterozygous genotypes like a

A cross is made between double heterozygous genotypes, like a Mendelian F₁ x F₁ (e.g. AaBb x AaBb).

What fraction of the F₂ progeny would be expected to show pattern I?

P1NP2 A n B n C n D n E n F G H n I

Lets number each row as 1,2,3,4 in the gel.

Step 1. First we need to find the alleles of a gene. Since parents are heterozygous it is understood that there are 2 genes only.

Lane C shows that 1 and 2 are not alleles. (absence of band)

Lane G shows that 3 and 4 are not alleles. (absence of band)

Lane I shows that 2 and 3 are not alleles (absence of band)

Hence it can be implied that

A. 1 and 3 are alleles

B. 2 and 4 are alleles

Step 2 Lane I observation

Only one band in 1 and 3 - homozygous

Only one band in 2 and 4 - homozygous

Fraction = (1/4) * (1/4) = 1/16

$A cross is made between double heterozygous genotypes, like a Mendelian F1 x F1 (e.g. AaBb x AaBb). What fraction of the F2 progeny would be expected to show pa$

A cross is made between double heterozygous genotypes like a

Solution

Get Help Now

Submit a Take Down Notice