Liquid hexane CH3 CH2 CH Will react with gaseous oxygen O2 t

Liquid hexane (CH3 (CH2 CH Will react with gaseous oxygen (O2) to produce gaseous carbon dioxide (CO2) and gaseous waSuppose 59. 9 of hexane is mixed with 126. g of oxygen. Calculate the maximum mass of water that could be produced by the chemical reaction. Round your answer to significant digits. 0e Ar

Solution

Answer

52.3g

Explanation

2CH3(CH2)4CH3(l) + 19O2(g) - - - > 12CO2(g) + 14H2O(g)

Stoichiometrically, 19moles of O2 reacting with 2moles of Hexane to produce 14moles of H2O

given moles of Hexane = 59g/86.18g/mol = 0.68461

given moles of O2 = 126g/32g/mol= 3.9375

0.68461moles of Hexane need (19/2)×0.68461 = 6.5038moles for complete burning but available moles of O2 is 3.9375moles

Therefore,

Oxygen is limiting reagent

3.9375moles of O2 give (14/19)×3.9375= 2.9013moles of H2O

Maximum mass of H2O could produced = 2.9013moles × 18.02g =52.3g