Find the equation of the line in the figure below Solutionli

Find the equation of the line in the figure below.

line L₁ passes through point (0,3) and (4,0)

slope of line L₁, m₁ = (0-3)/(4-0) = -3/4

now product of slopes of two perpandicular lines = -1

therefore m₁m₂ = -1

m₂ = -1/(-3/4) = 4/3

also L₂ passes through origin.

equation of line L₂ is

y = m₂x

y = (4/3)x

=> 3y = 4x