A reaction has a rate consant of 123mols at 433 Celcius and

A reaction has a rate consant of 1.23/mol*s at 433 Celcius and 24/mol*s at 533celcius. Determine the activation energy for this reaction?

Solution

433c = 706K , = T1, T2 = 533C = 806 K ,

ln(k2/k1) = (E/R)(1/T1-1/T2) ,

ln(24/1.23) = E/(8.314) [1/706 - 1/806]

E = 140807 J/mol = 140.807 KJ/mol is activation energy