How many seconds are required to produce 700 g of aluminum m

How many seconds are required to produce 7.00 g of aluminum metal from the electrolysis of molten AlCl3 with an electrical current of 12.0 A?

Solution

Answer moles Al = 4/ 26.98 = 0.148 Al3+ + 3e- >> Al This means to get 0.148 mole Al we need to use 0.0148 mol x ( 3 Faradays / 1 mol) = 0.444 Faradays but 1 F = 96500 Coulombs 0.444 F = 0.444 F ( 96500 C / F) = 42846 C If the corrent is 12.0 amp ( or 12.0 Coulomb/s) to get 42846 C we need to wait 42846 C / 12.0 C/s = 3570.5 s