what volume of HCLg measured at STP can be produced from 209

what volume of HCL(g) measured at STP can be produced from 2.09 g H2 (g) and excess Cl2(g)? Please show work

Solution

moles of H2=2.09/2

=1.045

so

H2+Cl2---> 2HCl

so moles of HCl=1.045*2

=2.09

so volume be v.so,

v*1=2.1*273/12

or v=47.775 l