refresh please The steel tank with volume of 438 L filled wi

refresh please

The steel tank with volume of 438 L filled with certain amount of O2 develops a slow leak that pressure is 1.37 atm at 25 °C. How many grams of O2 remain? is discovered and sealed. A pressure gauge fitted on the tank shows the new

Solution

volume of tank =438L, P= 1.37 atm and T= 25 deg.c= 25+273= 298K

During leak, some gas is lost, but the volume does not change

from gas law, moles of oxygen remaining , n= PV/RT= 1.37*438/(0.0821 L.atm/mole.K* 298)= 24.52 moles of O2